document.write( "Question 985427: A cashier has a total of 33 bills consisting of ones, fives and twenties. The number of twenties is 12 less than the number of ones. The total value of money is $183. How many of each denomination of bill are there?\r
\n" );
document.write( "\n" );
document.write( "Thank you. \n" );
document.write( "
Algebra.Com's Answer #606221 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x=ones \n" ); document.write( "x-12=twenties. \n" ); document.write( "Their sum is 2x-12, so \n" ); document.write( "33-(2x-12)=fives \n" ); document.write( "x+20(x-12)+5(45-2x)=183 \n" ); document.write( "collect terms after distributing \n" ); document.write( "x+20x-240+225-10x=183 \n" ); document.write( "11x-15=183 \n" ); document.write( "11x=198 \n" ); document.write( "x=18 \n" ); document.write( "x-12=6 \n" ); document.write( "33-(2x-12)=9 \n" ); document.write( "There are 33 bills \n" ); document.write( "18 are ones for $18 \n" ); document.write( "9 are fives for $45 \n" ); document.write( "6 are twenties for $120 \n" ); document.write( "Total is 33 for $183. \n" ); document.write( " |