document.write( "Question 985427: A cashier has a total of 33 bills consisting of ones, fives and twenties. The number of twenties is 12 less than the number of ones. The total value of money is $183. How many of each denomination of bill are there?\r
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Algebra.Com's Answer #606221 by Boreal(15235)\"\" \"About 
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x=ones
\n" ); document.write( "x-12=twenties.
\n" ); document.write( "Their sum is 2x-12, so
\n" ); document.write( "33-(2x-12)=fives
\n" ); document.write( "x+20(x-12)+5(45-2x)=183
\n" ); document.write( "collect terms after distributing
\n" ); document.write( "x+20x-240+225-10x=183
\n" ); document.write( "11x-15=183
\n" ); document.write( "11x=198
\n" ); document.write( "x=18
\n" ); document.write( "x-12=6
\n" ); document.write( "33-(2x-12)=9
\n" ); document.write( "There are 33 bills
\n" ); document.write( "18 are ones for $18
\n" ); document.write( "9 are fives for $45
\n" ); document.write( "6 are twenties for $120
\n" ); document.write( "Total is 33 for $183.
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