document.write( "Question 985208: Akosua is A years now. Abigail is B years older than Akosua. In ( X + 2 ) years time, AKosua will be half as old as Abigail. Find X \n" ); document.write( "
Algebra.Com's Answer #606202 by ankor@dixie-net.com(22740)\"\" \"About 
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let ak = Akosua's age
\n" ); document.write( "let ab = Abigail's age
\n" ); document.write( ":
\n" ); document.write( "Akosua is A years now.
\n" ); document.write( "ak = A
\n" ); document.write( ":
\n" ); document.write( "Abigail is B years older than Akosua.
\n" ); document.write( "ab = ak + B
\n" ); document.write( "
\n" ); document.write( "In (X + 2) years time, AKosua will be half as old as Abigail.
\n" ); document.write( "ak + (x+2) = \"1%2F2\"(ab+ (x+ 2))
\n" ); document.write( "multiply both sides by 2
\n" ); document.write( "2(ak + x + 2) = ab + x + 2
\n" ); document.write( "2ak + 2x + 4 = ab + x + 2
\n" ); document.write( "2ak + 2x - x = ab + 2 - 4
\n" ); document.write( "2ak + x = ab - 2
\n" ); document.write( "replace ab with (ak+B)
\n" ); document.write( "2ak + x = ak + B - 2
\n" ); document.write( "x = ak - 2ak + B - 2
\n" ); document.write( "x = -ak + B - 2
\n" ); document.write( "Replace Ak with A
\n" ); document.write( "x = -A + B - 2
\n" ); document.write( "
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