document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=985391>Question 985391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I graph y=3x^2-2x-5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #606200 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=606200\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Step 1, y-intercept.  x=0, y=-5 from the equation.  That is your first point.<BR>\n" );
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document.write( "Step 2: find the vertex.  The x-value is (-b/2a)=(2/6)=1/3. <BR>\n" );
document.write( "the y-value is (1/3)-2/3-5=4 2/3.  (1/3, -16/3) is the vertex.  The x^2 coefficient is positive, so this is convex downward.<BR>\n" );
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document.write( "Step 3: From the vertex to the y-intercept, you go left (1/3) unit and up 1/3 unit to (0,-5)<BR>\n" );
document.write( "Step 4: Use symmetry, and go right 1/3 unit and up 1/3 unit.  You have 3 points and can graph it, but these points are very close together.  Therefore,<BR>\n" );
document.write( "Step 5: Find zeros: This factors into (3x-5)(x+1)=0, so zeros are at x=(5/3) and -1. That gives 5 points.\r<BR>\n" );
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