document.write( "Question 985375: Divide 50 into two parts such that the product is maximum \n" ); document.write( "
Algebra.Com's Answer #606186 by macston(5194)\"\" \"About 
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\n" ); document.write( "Let y=the maximum product
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\n" ); document.write( "y=x(50-x) The maximum is when first derivative of the function=0
\n" ); document.write( "y=50x-x^2
\n" ); document.write( "dy/dx=50-2x Set derivative=0
\n" ); document.write( "0=50-2x
\n" ); document.write( "-50=-2x
\n" ); document.write( "25=x ANSWER: The product is maximum when both parts are 25.
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