document.write( "Question 985375: Divide 50 into two parts such that the product is maximum \n" ); document.write( "
Algebra.Com's Answer #606186 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Let y=the maximum product \n" ); document.write( ". \n" ); document.write( "y=x(50-x) The maximum is when first derivative of the function=0 \n" ); document.write( "y=50x-x^2 \n" ); document.write( "dy/dx=50-2x Set derivative=0 \n" ); document.write( "0=50-2x \n" ); document.write( "-50=-2x \n" ); document.write( "25=x ANSWER: The product is maximum when both parts are 25. \n" ); document.write( " |