document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=985362>Question 985362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let &#952; be an angle in quadrant III, such that csc &#952;= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-9%2F8 ALIGN=MIDDLE  ALT=\"-9%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Find tan &#952; & cos &#952;:\r<BR>\n" );
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document.write( "So far, I found that cos&#952; = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-8%2F9 ALIGN=MIDDLE  ALT=\"-8%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "As for tan&#952;, I think it is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+8sqrt%28+17+%29%2F%289%29+ ALIGN=MIDDLE  ALT=\"+8sqrt%28+17+%29%2F%289%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "I got that through <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-9%5E2+=+8%5E2+%2B+x%5E2 ALIGN=MIDDLE  ALT=\"-9%5E2+=+8%5E2+%2B+x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > with x= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2817%29 ALIGN=MIDDLE  ALT=\"sqrt%2817%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "And using that, I saw that tan&#952;'s equation would be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%2817%29%2F%28-9%29%29 ALIGN=MIDDLE  ALT=\"%28sqrt%2817%29%2F%28-9%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > all over <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-8%2F9 ALIGN=MIDDLE  ALT=\"-8%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Right up until I finished typing up this question, I just realized that I misused the reciprocals, oops. I would still like to know the proper answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #606169 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=606169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> csc theta = -9/8<BR>\n" );
document.write( "note that csc theta = 1 / sin (theta), therefore<BR>\n" );
document.write( "1 / sin theta = -9 / 8<BR>\n" );
document.write( "sin theta = -8 / 9<BR>\n" );
document.write( "inverse sin theta = &#8722;62.733955549 approx -62.7<BR>\n" );
document.write( "theta is in quadrant III, theta = 270 - 62.7 =  207.3 degrees<BR>\n" );
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document.write( "cos 207.3 = &#8722;0.888617233<BR>\n" );
document.write( "tan 207.3 =  0.516138488<BR>\n" );
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