document.write( "Question 985278: Given x > 1, solve for x \r
\n" ); document.write( "\n" ); document.write( "(log x^7)(log x) − log x^2 − 5 = 0
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Algebra.Com's Answer #606099 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
\"log%28x%5E7%29%2Alog%28x%29+-+log%28x%5E2%29+-+5+=+0\"
\n" ); document.write( "\"7%2Alog%28x%29%2Alog%28x%29+-+2%2Alog%28x%29+-+5+=+0+\"
\n" ); document.write( "\"+7%2Alog%28x%29%5E2+-+2+log%28x%29+-+5+=+0\"
\n" ); document.write( "Let \"+y+=+log%28x%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"+7y%5E2+-+2y+-+5+=+0\"\r
\n" ); document.write( "\n" ); document.write( "Use quadratic formula\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28-%28-2%29+%2B-+sqrt%28%28-2%29%5E2+-+4%2A7%2A%28-5%29%29%29%2F%282%2A7%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%282+%2B-+sqrt%284%2B140%29%29%2F14\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%282+%2B-+12%29+%2F+14\"\r
\n" ); document.write( "\n" ); document.write( "\"+y+=+-6%2F14+%2C+1+\"\r
\n" ); document.write( "\n" ); document.write( "First, deal with \"y+=+-6%2F14\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-6%2F14\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28x%29+=+-6%2F14\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+10%5E%28-6%2F14%29+=+.373\"\r
\n" ); document.write( "\n" ); document.write( "Now deal with \"y+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28x%29+=+1\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+10%5E1+=+10\"\r
\n" ); document.write( "\n" ); document.write( "Since \".373+%3C+1\", then we only accept \"highlight%28x+=+10%29\"
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