document.write( "Question 84140: Use the geometric sequence of numbers 1, 1/2, 1/4, 1/8,.....to find the following:\r
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document.write( "a) What is r, the ratio between 2 consecutive terms?
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document.write( " Answer: r=1/2 divided by 1,\r
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document.write( " which is 1/2(fraction)
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document.write( "Is this correct\r
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document.write( "b) Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 10 terms? Round your answer to 4 decimals.
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document.write( "show work\r
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document.write( "1st term is 1X1/2=1/2
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document.write( "2nd term is 1/2X1/2=1/4
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document.write( "3rd term is 1/4X1/2=1/8
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document.write( "4th term is 1/8X1/2=1/16
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document.write( "5th term is 1/16X1/2=1/32
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document.write( "6th term is 1/32X1/2=1/64
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document.write( "7th term is 1/64X1/2=1/128
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document.write( "8th term is 1/128X1/2=1/256
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document.write( "9th term is 1/256X1/2=1/512
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document.write( "10th term is 1/512X1/2=1,024\r
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document.write( "c)Using the formula for the sum of the first n terms of a geometric series, what is the sum of the first 12 terms? Round to 4 decimals.
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document.write( "show work\r
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document.write( "11th term is 1/1,024X1/2=2,048
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document.write( "12 term is 1/2,048X1/2=4,096\r
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document.write( "d) What observation can you make about these sums? In particular, what whole number does it appear that the sum will always be smaller than?
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Algebra.Com's Answer #60609 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! a) \n" ); document.write( "The ratio r is the factor to get from term to term. So \n" ); document.write( "r=nth term/(n-1) term \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the ratio is \n" ); document.write( "The sequence is cut in half each term, so the sequence is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b) \n" ); document.write( "The sum of a geometric series is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the sum of the first ten terms is \n" ); document.write( "\n" ); document.write( "c) \n" ); document.write( "Use the same formula to find the sum of the 1st 12 terms \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So the sum of the first twelve terms is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d) \n" ); document.write( "It appears that the sums are approaching a finite number of 2. This is because each term is getting smaller and smaller. This observation is justified by the fact that if \n" ); document.write( "If \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |