document.write( "Question 985183: Miguel is now twice as old as Pauline. Five years ago Miguel was three times as old as Pauline. Find their present ages.
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Algebra.Com's Answer #606028 by ikleyn(52797) $\"\"$ $\"About$

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\n" ); document.write( "Let x be the Pauline's present age.\r
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\n" ); document.write( "\n" ); document.write( "Then the Miguel's present age is 2x, in accordance with the condition. \r
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\n" ); document.write( "\n" ); document.write( "Five years ago Miguel's age was (2x-5) and Pauline's age was (x-5).\r
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\n" ); document.write( "\n" ); document.write( "In accordance with the condition, you have an equation\r
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\n" ); document.write( "\n" ); document.write( "2x-5 = 3*(x-5).\r
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\n" ); document.write( "\n" ); document.write( "Solve it step by step:\r
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\n" ); document.write( "\n" ); document.write( "2x - 5 = 3x - 15,\r
\n" ); document.write( "\n" ); document.write( "-5 + 15 = 3x - 2x,\r
\n" ); document.write( "\n" ); document.write( "10 = x.\r
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\n" ); document.write( "\n" ); document.write( "Thus Pauline's present age is 10 years. \r
\n" ); document.write( "\n" ); document.write( "Hence, Miguel's present age is 2*10 = 20 years. \r
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