document.write( "Question 985181: 2. The total of ages of X, Y and Z is 27. X is 2 years older than Y who happens to be twice as old as Z. What is the age of Y?
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Algebra.Com's Answer #606025 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "2. \r
\n" ); document.write( "\n" ); document.write( "if the total of ages of \"X\", \"Y+\"and \"Z\" is \"27\", then we have\r
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\n" ); document.write( "\n" ); document.write( "\"X%2BY+%2B+Z+=27\"\r
\n" ); document.write( "\n" ); document.write( "if \"X\" is \"2+\"years older than \"Y\", then\r
\n" ); document.write( "\n" ); document.write( "\"X=Y%2B2\" \r
\n" ); document.write( "\n" ); document.write( "if \"Y\" happens to be twice as old as \"Z\", then\r
\n" ); document.write( "\n" ); document.write( "\"Y=2Z\"=>\"Z=Y%2F2\"\r
\n" ); document.write( "\n" ); document.write( "substitute \"Y%2B2\" for \"X\" and \"Y%2F2\" for \"Z\"\r
\n" ); document.write( "\n" ); document.write( "\"Y%2B2%2BY+%2B+Y%2F2+=27\"\r
\n" ); document.write( "\n" ); document.write( "\"2Y%2F2%2B2Y%2F2+%2B+Y%2F2+=27-2\"\r
\n" ); document.write( "\n" ); document.write( "\"5Y%2F2+=25\"\r
\n" ); document.write( "\n" ); document.write( "\"5Y+=25%2A2\"\r
\n" ); document.write( "\n" ); document.write( "\"5Y+=50\"\r
\n" ); document.write( "\n" ); document.write( "\"Y+=50%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28Y+=10%29\"\r
\n" ); document.write( "\n" ); document.write( "now we can find \"X\" and \"Z\"\r
\n" ); document.write( "\n" ); document.write( "\"X=Y%2B2\" =>\"X=12\" \r
\n" ); document.write( "\n" ); document.write( "\"Z=Y%2F2\"=>\"Z=5\"\r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "\"X%2BY+%2B+Z+=27\"
\n" ); document.write( "\"12%2B10+%2B+5+=27\"
\n" ); document.write( "\"27+=27\"\r
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