document.write( "Question 985039: If you consider the numbers 1,2,3,4, and 5, how many three digit numbers can be formed if:
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document.write( "A. Repetition is not allowed and such that they are all:\r
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document.write( "1. Greater than 200
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document.write( "2. Ending in 5
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document.write( "3. odd numbers\r
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document.write( "B. Repetition is allowed such that they are all:
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document.write( "1. even numbers
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document.write( "2. Less than 500
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document.write( "3. having 1 or 5 in their hundreds place \n" );
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Algebra.Com's Answer #605973 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A. Repetition is not allowed and such that they are all: \n" ); document.write( "1. Greater than 200 \n" ); document.write( "The hundreds unit must be greater than 1, so there are 4 choices, 4 remaining choices for tens, and 3 choices for units: \n" ); document.write( "4 x 4 x 3 = 48 possible numbers \n" ); document.write( ". \n" ); document.write( "2. Ending in 5 \n" ); document.write( "One choice for units, 4 remaining for tens, 3 for hundreds: \n" ); document.write( "1 x 4 x 3 = 12 possible numbers \n" ); document.write( ". \n" ); document.write( "3. odd numbers \n" ); document.write( "Three choices for units, 4 remaining for tens, 3 for hundreds: \n" ); document.write( "3 x 4 x 3 = 36 possible numbers \n" ); document.write( ". \n" ); document.write( "B. Repetition is allowed such that they are all: \n" ); document.write( "1. even numbers \n" ); document.write( "Two choices for units, 5 for tens and 5 for hundreds: \n" ); document.write( "2 x 5 x 5 = 50 possible numbers \n" ); document.write( ". \n" ); document.write( "2. Less than 500 \n" ); document.write( "Three choices for hundreds, 5 for tens, 5 for units: \n" ); document.write( "3 x 5 x 5 =75 possible numbers \n" ); document.write( ". \n" ); document.write( "3. having 1 or 5 in their hundreds place \n" ); document.write( "2 choices for hundreds, 5 for tens, five for units: \n" ); document.write( "2 x 5 x 5 = 50 possible numbers \n" ); document.write( " |