document.write( "Question 985133: At a pet shop there were 10 more dogs than cats. The shop sold 2 dogs and bought 2 cats. Now there are twice as many dogs than cats. How many cats does the shop have now? \n" ); document.write( "
Algebra.Com's Answer #605964 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "D=original number of dogs; C= original number of cats \n" ); document.write( ". \n" ); document.write( "D=C+10 Ten more dogs than cats \n" ); document.write( ". \n" ); document.write( "D-2=2(C+2) Substitute for C \n" ); document.write( "(C+10)-2=2(C+2) \n" ); document.write( "C+8=2C+4 \n" ); document.write( "4=C The shop originally had 4 cats. \n" ); document.write( "The shop bought two cats so: \n" ); document.write( "4+2=6 \n" ); document.write( "ANSWER: The shop now has 6 cats. \n" ); document.write( ". \n" ); document.write( "Original number of dogs: \n" ); document.write( "D=C+10=4+10=14 The shop originally had 14 dogs. \n" ); document.write( "The shop sold two dogs: \n" ); document.write( "14-2=12 The shop now has 12 dogs. \n" ); document.write( "12 dogs is twice as many as 6 cats. \n" ); document.write( " |