document.write( "Question 985133: At a pet shop there were 10 more dogs than cats. The shop sold 2 dogs and bought 2 cats. Now there are twice as many dogs than cats. How many cats does the shop have now? \n" ); document.write( "
Algebra.Com's Answer #605964 by macston(5194)\"\" \"About 
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\n" ); document.write( "D=original number of dogs; C= original number of cats
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\n" ); document.write( "D=C+10 Ten more dogs than cats
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\n" ); document.write( "D-2=2(C+2) Substitute for C
\n" ); document.write( "(C+10)-2=2(C+2)
\n" ); document.write( "C+8=2C+4
\n" ); document.write( "4=C The shop originally had 4 cats.
\n" ); document.write( "The shop bought two cats so:
\n" ); document.write( "4+2=6
\n" ); document.write( "ANSWER: The shop now has 6 cats.
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\n" ); document.write( "Original number of dogs:
\n" ); document.write( "D=C+10=4+10=14 The shop originally had 14 dogs.
\n" ); document.write( "The shop sold two dogs:
\n" ); document.write( "14-2=12 The shop now has 12 dogs.
\n" ); document.write( "12 dogs is twice as many as 6 cats.
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