document.write( "Question 84147: Solve the system by addition \r
\n" ); document.write( "\n" ); document.write( "-3x+4y=-16
\n" ); document.write( " x-2y=12
\n" ); document.write( "

Algebra.Com's Answer #60591 by funmath(2933)\"\" \"About 
You can put this solution on YOUR website!
Solve the system by addition \r
\n" ); document.write( "\n" ); document.write( "-3x+4y=-16 R1
\n" ); document.write( " x-2y=12 R2
\n" ); document.write( "Multiply R2 by 3 and add it to R1 and the x's will be eliminated so you can solve for y.
\n" ); document.write( "3R2===> 3(x-2y)=3(12)===> 3x-6y=36
\n" ); document.write( "R1+3R2 is
\n" ); document.write( "-3x+4y=-16
\n" ); document.write( " 3x-6y=36
\n" ); document.write( "----------
\n" ); document.write( " 0-2y=20
\n" ); document.write( "-2y=20
\n" ); document.write( "-2y/-2=20/-2
\n" ); document.write( "y=-10
\n" ); document.write( "Now substitute 10 in for y in R2 (because it's easier than R1) and solve for x:
\n" ); document.write( "x-2(-10)=12
\n" ); document.write( "x+20=12
\n" ); document.write( "x+20-20=12-20
\n" ); document.write( "x=-8
\n" ); document.write( "The solution to the system is (x,y)=(-8,-10)
\n" ); document.write( "Happy Calculating!!!!
\n" ); document.write( "
\n" );