document.write( "Question 985052: Give the equation of the circle tangent to both axes, of radius 5 and in the 1st quadrant. In the 2nd Quadrant.In the 3rd quadrant. In the 4th quadrant. \n" ); document.write( "
Algebra.Com's Answer #605884 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "The distance from each axis to center of circle must equal radius for the circle to be tangent to both axes.
\n" ); document.write( ".
\n" ); document.write( "In the first quadrant, center of circle is +5 from each axis, center at (5,5)
\n" ); document.write( ".
\n" ); document.write( "In second quadrant, center of circle is +5 from y axis (x=5) and 5 below x axis (y=-5), center at (5,-5)
\n" ); document.write( ".
\n" ); document.write( "In third quadrant, center of circle is 5 left of y axis (x=-5) and 5 below x axis (y=-5), center at (-5,-5)
\n" ); document.write( ".
\n" ); document.write( "In fourth quadrant, center of circle is 5 left of y axis (x=-5), 5 above x axis (y=5), center at (-5,5)
\n" ); document.write( ".
\n" ); document.write( "Standard form of circle:
\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"
\n" ); document.write( "where (h,k) is the center and r is the radius
\n" ); document.write( ".
\n" ); document.write( "First quadrant: h=5; k=5; r=5
\n" ); document.write( "\"%28x-5%29%5E2%2B%28y-5%29%5E2=25\"
\n" ); document.write( ".
\n" ); document.write( "Second quadrant: h=5; k=-5; r=5
\n" ); document.write( "\"%28x-5%29%5E2%2B%28y%2B5%29%5E2=25\"
\n" ); document.write( ".
\n" ); document.write( "Third quadrant: h=-5; k=-5; r=5
\n" ); document.write( "\"%28x%2B5%29%5E2%2B%28y%2B5%29%5E2=25\"
\n" ); document.write( ".
\n" ); document.write( "Fourth quadrant: h=-5; k=5; r=5
\n" ); document.write( "\"%28x%2B5%29%5E2%2B%28y-5%29%5E2=25\"
\n" ); document.write( "
\n" );