document.write( "Question 985052: Give the equation of the circle tangent to both axes, of radius 5 and in the 1st quadrant. In the 2nd Quadrant.In the 3rd quadrant. In the 4th quadrant. \n" ); document.write( "
Algebra.Com's Answer #605884 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "The distance from each axis to center of circle must equal radius for the circle to be tangent to both axes. \n" ); document.write( ". \n" ); document.write( "In the first quadrant, center of circle is +5 from each axis, center at (5,5) \n" ); document.write( ". \n" ); document.write( "In second quadrant, center of circle is +5 from y axis (x=5) and 5 below x axis (y=-5), center at (5,-5) \n" ); document.write( ". \n" ); document.write( "In third quadrant, center of circle is 5 left of y axis (x=-5) and 5 below x axis (y=-5), center at (-5,-5) \n" ); document.write( ". \n" ); document.write( "In fourth quadrant, center of circle is 5 left of y axis (x=-5), 5 above x axis (y=5), center at (-5,5) \n" ); document.write( ". \n" ); document.write( "Standard form of circle: \n" ); document.write( " \n" ); document.write( "where (h,k) is the center and r is the radius \n" ); document.write( ". \n" ); document.write( "First quadrant: h=5; k=5; r=5 \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Second quadrant: h=5; k=-5; r=5 \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Third quadrant: h=-5; k=-5; r=5 \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Fourth quadrant: h=-5; k=5; r=5 \n" ); document.write( " |