document.write( "Question 985023: present age of father is 5 more than 4 times the age of his son. if sum of their present ages is 45 .find the difference between their ages \n" ); document.write( "
Algebra.Com's Answer #605866 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "F=age of father; S=age of son \n" ); document.write( "F=4S+5 \n" ); document.write( ". \n" ); document.write( "F+S=45 \n" ); document.write( "(4S+5)+S=45 \n" ); document.write( "5S=40 \n" ); document.write( "S=8 The son is 8 years old. \n" ); document.write( "F=4S+5=4(8)+5=32+5=37 The father is 37 years old. \n" ); document.write( "F-S=37-8=29 ANSWER: The difference in their ages is 29 years. \n" ); document.write( " |