document.write( "Question 985023: present age of father is 5 more than 4 times the age of his son. if sum of their present ages is 45 .find the difference between their ages \n" ); document.write( "
Algebra.Com's Answer #605866 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "F=age of father; S=age of son
\n" ); document.write( "F=4S+5
\n" ); document.write( ".
\n" ); document.write( "F+S=45
\n" ); document.write( "(4S+5)+S=45
\n" ); document.write( "5S=40
\n" ); document.write( "S=8 The son is 8 years old.
\n" ); document.write( "F=4S+5=4(8)+5=32+5=37 The father is 37 years old.
\n" ); document.write( "F-S=37-8=29 ANSWER: The difference in their ages is 29 years.
\n" ); document.write( "
\n" );