document.write( "Question 985020: 100 - (3x + 2y) = 50 \n" ); document.write( "
Algebra.Com's Answer #605864 by macston(5194)\"\" \"About 
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\n" ); document.write( "100-(3x+2y)=50
\n" ); document.write( "-(3x+2y)=-50
\n" ); document.write( "3x+2y=50
\n" ); document.write( "3x+2y-50=0
\n" ); document.write( "
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