document.write( "Question 84145: Jon invested $21,000, part at 18% and part at 8%. If the total interest at the end of the year is $1,980, how much did he invest at 18%. \n" ); document.write( "
Algebra.Com's Answer #60586 by checkley75(3666)\"\" \"About 
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.18X+.08(21000-X)=1980
\n" ); document.write( ".18X+1680-.08X=1980
\n" ); document.write( ".1X=1980-1680
\n" ); document.write( ".1X=300
\n" ); document.write( "X=300/.1
\n" ); document.write( "X=3000 AMOUNT INVESTED @ 18%.
\n" ); document.write( "PROOF
\n" ); document.write( ".18*3000+.08(21000-3000)=1980
\n" ); document.write( "540+.08(18000)=1980
\n" ); document.write( "540+1440=1980
\n" ); document.write( "1980=1980
\n" ); document.write( "
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