document.write( "Question 984921: Container A and Container B had 50.36 liter of water.After 9.05 liter of water was transferred from container A to B,Container A had thrice as much water as container B.How much water was in container A at first? \n" ); document.write( "
Algebra.Com's Answer #605815 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let a = original amt in container A \n" ); document.write( "let b = original amt in container B \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "Container A and Container B had 50.36 liter of water. \n" ); document.write( "a + b = 50.36 \n" ); document.write( "b = (50.36-a); use this form for substitution \n" ); document.write( ": \n" ); document.write( "After 9.05 liter of water was transferred from container A to B, Container A had thrice as much water as container B. \n" ); document.write( "a - 9.05 = 3(b + 9.05) \n" ); document.write( "a - 9.05 = 3b + 27.15 \n" ); document.write( "a = 3b + 27.15 + 9.05 \n" ); document.write( "a = 3b + 36.20 \n" ); document.write( ": \n" ); document.write( "How much water was in container A at first? \n" ); document.write( "Replace b with (50.36-a)) in the above equation \n" ); document.write( "a = 3(50.36 - a) + 36.2 \n" ); document.write( "a = 151.08 - 3a + 36.2 \n" ); document.write( "a + 3a = 151.08 + 36.2 \n" ); document.write( "4a = 187.28 \n" ); document.write( "a = 187.28/4 \n" ); document.write( "a = 46.82 liters originally \n" ); document.write( " |