document.write( "Question 984934: 1 + log2(-5x)=5 \n" ); document.write( "
Algebra.Com's Answer #605803 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "\"1\" + \"log%282%2C%28-5x%29%29\" = \"5\",\r
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\n" ); document.write( "\n" ); document.write( "\"log%282%2C%28-5x%29%29\" = \"4\",\r
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\n" ); document.write( "\n" ); document.write( "\"-5x\" = \"2%5E4\",\r
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\n" ); document.write( "\n" ); document.write( "-5x = 16,\r
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\n" ); document.write( "\n" ); document.write( "x = \"-16%2F5\" = \"-3\"\"1%2F5\".\r
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