document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984889>Question 984889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 9 times a number is increased by 12, the result is 10 times a number decreased by 4. Find the number.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #605702 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=605702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "x=a number<BR>\n" );
document.write( ".<BR>\n" );
document.write( "9x+12=10x-4<BR>\n" );
document.write( "16=x<BR>\n" );
document.write( "ANSWER: The number is 16<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "9x+12=10x-4<BR>\n" );
document.write( "9(16)+12=10(16)-4<BR>\n" );
document.write( "144+12=160-4<BR>\n" );
document.write( "156=156<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );