document.write( "Question 11857: how to use 'sin','cosin' and 'tangent'in triangles. \n" ); document.write( "
Algebra.Com's Answer #6057 by longjonsilver(2297)\"\" \"About 
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draw a right-angled triangle... a horizontal line AB and a vertical line BC at the right-end of the horizontal line. The hypotenuse is AC.\r
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\n" ); document.write( "\n" ); document.write( "Now, draw another vertical line DE where D is some point on line AB...your choice and E is the other end of the line, somewhere on AC. OK so far?\r
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\n" ); document.write( "\n" ); document.write( "Right, the angle A is whatever angle it is. The \"interesting\" or at least useful property is that the ratio of the sides in triangles ABC and ADE are the same... so AB/AC is the same as AD/AE etc.\r
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\n" ); document.write( "\n" ); document.write( "So, we can use this fact that ratios of sides for a given angle are the same. Now there are 3 possible combinations of sides (well 6 actually). These are:\r
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\n" ); document.write( "\n" ); document.write( "opposite/adjacent
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\n" ); document.write( "\n" ); document.write( "opposite/hypotenuse
\n" ); document.write( "hypotenuse/opposite\r
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\n" ); document.write( "\n" ); document.write( "adjacent/hypotenuse
\n" ); document.write( "hypotenuse/adjacent\r
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\n" ); document.write( "\n" ); document.write( "and these ratios have names:\r
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\n" ); document.write( "\n" ); document.write( "opposite/adjacent --> tangent
\n" ); document.write( "adjacent/opposite --> cotangent\r
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\n" ); document.write( "\n" ); document.write( "opposite/hypotenuse --> sine
\n" ); document.write( "hypotenuse/opposite --> cosecant\r
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\n" ); document.write( "\n" ); document.write( "adjacent/hypotenuse --> cosine
\n" ); document.write( "hypotenuse/adjacent --> secant\r
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\n" ); document.write( "\n" ); document.write( "For basic trig, you will use SIN, COS and TAN, the 3 \"basic\" ratios.\r
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\n" ); document.write( "\n" ); document.write( "jon.
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