document.write( "Question 984866: A pool has a perimeter of 176 ft, and a length that is three time the width. What's the pool's area? \n" ); document.write( "
Algebra.Com's Answer #605693 by macston(5194) You can put this solution on YOUR website! . \n" ); document.write( "W=width; L=length=3W; P=perimeter \n" ); document.write( ". \n" ); document.write( "P=2(L+W) \n" ); document.write( "176ft=2(3W+W) \n" ); document.write( "88ft=4W \n" ); document.write( "22ft=W The width is 22 feet. \n" ); document.write( "L=3W=3(22ft)=66ft The length is 66 feet. \n" ); document.write( ". \n" ); document.write( "Area=LW \n" ); document.write( "Area=(66ft)(22ft)=1452 sq ft \n" ); document.write( "ANSWER: The area of the pool is 1452 square feet. \n" ); document.write( " \n" ); document.write( " |