document.write( "Question 984866: A pool has a perimeter of 176 ft, and a length that is three time the width. What's the pool's area? \n" ); document.write( "
Algebra.Com's Answer #605693 by macston(5194)\"\" \"About 
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\n" ); document.write( "W=width; L=length=3W; P=perimeter
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\n" ); document.write( "P=2(L+W)
\n" ); document.write( "176ft=2(3W+W)
\n" ); document.write( "88ft=4W
\n" ); document.write( "22ft=W The width is 22 feet.
\n" ); document.write( "L=3W=3(22ft)=66ft The length is 66 feet.
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\n" ); document.write( "Area=LW
\n" ); document.write( "Area=(66ft)(22ft)=1452 sq ft
\n" ); document.write( "ANSWER: The area of the pool is 1452 square feet.
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