document.write( "Question 984790: The price of my Chevrolet spark depreciates by 10% every year. If I bought it for 3.6 lakhs in the year 2011, by what price would it's price have fallen in 2015? \n" ); document.write( "
Algebra.Com's Answer #605644 by Timnewman(323)![]() ![]() You can put this solution on YOUR website! Hi dear, \n" ); document.write( "Since it depriciate every year by 10% given that its ammount is 3.6laks, \n" ); document.write( "Therefore,From 2011 to 2015 is 4yrs \n" ); document.write( "Then, \n" ); document.write( " From 2011--2012, \n" ); document.write( "The ammount after depreciation =3.6*10% \n" ); document.write( " =0.36 \n" ); document.write( "From 2012--2013; \n" ); document.write( "The ammount after depriciation=0.36*10% \n" ); document.write( " =0.036lakhs \n" ); document.write( "From 2013--2014, \n" ); document.write( "Ammount after depriciation =0.036*10% \n" ); document.write( " =0.0036lakhs \n" ); document.write( "From 2014---2015, \n" ); document.write( "Ammount after depriciation=0.0036*10% \n" ); document.write( " =0.00036lakhs \n" ); document.write( "The ammount after 2015 depriciation is 0.00036lakhs \n" ); document.write( "i,e 3.6*10^(-4)lakhs \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |