document.write( "Question 984778: a truck dives along the highway at a constant rate of 60 mph, as it passes a rest area. Exactly 9 minutes later, a truck driving 70 mph passes the same rest area. how long will it take the faster try k to catch up to the slower truck? how far from the rest area will they beat that time? \n" ); document.write( "

Algebra.Com's Answer #605628 by Fombitz(32388) $\"\"$ $\"About$

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Convert the 9 minutes to hours.
\n" ); document.write( " $\"T=9%2F60=3%2F20\"$
\n" ); document.write( "So if we start the clock when the second truck passes the rest area, the first truck is,
\n" ); document.write( " $\"D%5B1%5D=R%2AT=60%2A%283%2F20%29=9\"$ $\"mi\"$ ahead.
\n" ); document.write( "So then,
\n" ); document.write( " $\"R%5B1%5D%2At%2B9=R%5B2%5D%2At\"$
\n" ); document.write( " $\"60t%2B9=70t\"$
\n" ); document.write( " $\"10t=9\"$
\n" ); document.write( " $\"t=10%2F9\"$ $\"hr\"$
\n" ); document.write( "or approximately,
\n" ); document.write( " $\"t=%2810%2F9%2960=600%2F9=66%262%2F3\"$ $\"min\"$
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "The distance from the rest area would be,
\n" ); document.write( " $\"D=70%2810%2F9%29=700%2F9=77%267%2F9\"$ $\"mi\"$ \n" ); document.write( "

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