document.write( "Question 984786: How do I write the point-slope form of the line which passes through the point (-9,-3) and is parallel to the line \"x%2F3+%2B2+=+-3y\". Then write the general form of the equation. \n" ); document.write( "
Algebra.Com's Answer #605606 by josgarithmetic(39617)\"\" \"About 
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\"x%2F3+%2B2+=+-3y\",your given equation\r
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\n" ); document.write( "\n" ); document.write( "\"y=-x%2F9-2%2F3\", same equation in slope-intercept form.\r
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\n" ); document.write( "\n" ); document.write( "A line parallel to it will have slope \"-1%2F9\", which is same as the slope of the given line. This line parallel containing the given point, and in POINT-SLOPE form is \"y-%28-3%29=-%281%2F9%29%28x-%28-9%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "You can do the rest. General Form takes a format Ax+By=C.
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