document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984754>Question 984754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A steamer is going downstream in a river and cover a distance between two villages in 20 hours and same distance it covers in 25 hours when he return back in upstream if the speed of the river is 4 km/h. Find the distance between two villages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #605589 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=605589\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ship speed=x<BR>\n" );
document.write( "current speed=4 kph<BR>\n" );
document.write( "The distance is (x+4)*20, units in km.<BR>\n" );
document.write( "It is also ((x-4)*25.<BR>\n" );
document.write( "Those two are equal.<BR>\n" );
document.write( ";<BR>\n" );
document.write( "(x+4)*20=(x-4)*25<BR>\n" );
document.write( "20x+80=25x-100<BR>\n" );
document.write( "-5x=-180<BR>\n" );
document.write( "x=36 km/h<BR>\n" );
document.write( ";<BR>\n" );
document.write( "The speed is 40 km/h downstream *20 hours or 800 km.<BR>\n" );
document.write( "Upstream, the speed is 32 km/h*25 hours or 800 km. \r<BR>\n" );
document.write( "\n" );
document.write( "800 km is the distance.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );