document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984753>Question 984753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A set of rectangle is constructed so that their sides are in the ratio length : width = 5 : &#8730;3 + 1\r<BR>\n" );
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document.write( "If the rectangle has a length of &#8730;2 metres, what is its width? (Please fully simplify and leave in surd form). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #605587 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=605587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length/width=5/sqrt(3)+1<BR>\n" );
document.write( "sqrt(2)/W=5/sqrt(3)+1<BR>\n" );
document.write( "cross-multiply.  sqrt(2)*sqrt(3)=sqrt(2*3)=sqrt(6)<BR>\n" );
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document.write( "sqrt(6)+sqrt(2)=5W<BR>\n" );
document.write( "W=(1/5)[sqrt (6)+ sqrt(2)]<BR>\n" );
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document.write( "check: the ratio is approximately 5/2.7 or 1.85<BR>\n" );
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document.write( "sqrt(6)+sqrt(2) is about 3.9, and that divided by 5, is 0.78, just less than 0.8.<BR>\n" );
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document.write( "0.8*0.78=1.44, close enough to sqrt (2).<BR>\n" );
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