document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984762>Question 984762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of the following triangle: <BR>\n" );
document.write( "A=115°20', b=9.23m, c= 12.1m\r<BR>\n" );
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document.write( "(Round your answer to the nearest tenth of a square meter.)\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #605584 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=605584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area = (1/2)bc sin A, with two sides and an included angle.<BR>\n" );
document.write( "sin 115.333=0.9038<BR>\n" );
document.write( "A=(1/2)(0.9038)*9.23 m*12.1m<BR>\n" );
document.write( "=50.5 m^2 </SPAN>\n" );
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