document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984441>Question 984441</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A man has P1000 invested part of 5% and his remainder at 3% simple interest. The total income per year from these investment is P44. How much does he invested at the higher rate? P= Peso </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #605560 by </B><A HREF=/tutors/aboutme.mpl?userid=rushdi1987><B>rushdi1987(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rushdi1987><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rushdi1987><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=605560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I = PNR where I = interest , P = principal, N = time, R = rate of interest\r<BR>\n" );
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document.write( "Let he invested peso x at 5% interest and the rest (1000-x) @ 3% interest. \r<BR>\n" );
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document.write( "For 5% rate interest will be x*5/100*1 or x/20<BR>\n" );
document.write( "For 3% rate interest will be 1000-x*3/100*1 or 3(1000-x)/100\r<BR>\n" );
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document.write( "According to the qus \r<BR>\n" );
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document.write( "x/20 + 3(1000-x)/100 = 44<BR>\n" );
document.write( "or, 5x + 3(1000-x) = 44 * 100<BR>\n" );
document.write( "or, 5x + 3000 - 3x = 4400<BR>\n" );
document.write( "or, 2x = 4400-3000<BR>\n" );
document.write( "or, 2x = 1400<BR>\n" );
document.write( "or, x = 700\r<BR>\n" );
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document.write( "he invested p 700  at higher rate<BR>\n" );
document.write( " </SPAN>\n" );
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