document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984669>Question 984669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble figuring out part C of this problem:\r<BR>\n" );
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document.write( "A farm has the shape of a rectangle with an equilateral triangle on one end of the rectangle and a semicircle on the opposite end of the rectangle. The length of the rectangle is three times the radius of the semicircle. <BR>\n" );
document.write( "a.) Write a function for the perimeter of the farm in terms of the radius of the semicircle. <BR>\n" );
document.write( "b.) Write a function for the area of the farm in terms of the radius of the semicircle. <BR>\n" );
document.write( "c.) Write a function for the area of the farm in terms of the perimeter of the farm. <BR>\n" );
document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #605481 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=605481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length of rectangle (l) = 3 * r where r is the radius of the semicircle<BR>\n" );
document.write( "width of rectangle (w) = 2 * r<BR>\n" );
document.write( "side of triangle (s) = 2 * r<BR>\n" );
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document.write( "a) Perimeter (P) = circumference of semicircle + (2 * length of rectangle) + (2 * side of triangle)<BR>\n" );
document.write( "P = (pi * r) + (2 * 3 * r) + (4 * r) = r * (pi + 10) = 13.14 * r<BR>\n" );
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document.write( "b) Area (A) = (1/2) * Area of circle + Area of rectangle + area of equilateral triangle<BR>\n" );
document.write( "A = ((1/2) * pi * r^2) + (2 * r * 3 * r) + ((1/2) * (2 * r) * r*square root(3))<BR>\n" );
document.write( "A = r^2 * ( (pi/2) + 6 + (square root(3)) = 9.30 * r^2<BR>\n" );
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document.write( "c) A = P * r - 3.84<BR>\n" );
document.write( "note that pi is 3.14<BR>\n" );
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