document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984670>Question 984670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A grocer wants to make a ten pound mixture of peanuts and cashews that he can sell for $4.75 per pound.  If peanuts cost 4.00 dollars per pound and cashews cost 6.50 dollars per pound, how many pounds of each should he use?\r<BR>\n" );
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document.write( "How do I figure out the system of equations needed to solve this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #605477 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=605477\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "P=pounds of peanuts; C=pounds of cashews<BR>\n" );
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document.write( "P+C=10 pounds<BR>\n" );
document.write( "P=10-C Use this to substitute for P below.<BR>\n" );
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document.write( "$4.00P+$6.50C=($4.75/lb)(10 lbs) Substitute for P from above.<BR>\n" );
document.write( "$4.00(10-C)+$6.50C=$47.50<BR>\n" );
document.write( "$40.00-$4.00C+$6.50C=$47.50<BR>\n" );
document.write( "$2.50C=$7.50<BR>\n" );
document.write( "C=3 ANSWER 1: he should use 3 pounds of cashews.<BR>\n" );
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document.write( "P=10-C=10-3=7 ANSWER 2: He should use 7 pounds of peanuts.<BR>\n" );
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document.write( "CHECK:<BR>\n" );
document.write( "$4.00P+$6.50C=($4.75/lb)(10 lbs)<BR>\n" );
document.write( "$4.00(7)+$6.50(3)=$47.50<BR>\n" );
document.write( "$28.00+$19.50=$47.50<BR>\n" );
document.write( "$47.50=&47.50<BR>\n" );
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