document.write( "Question 984682: Find four consecutive even integers so that the sum of the first two added to twice the sum of the last two is egual to 742
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Algebra.Com's Answer #605468 by vleith(2983)\"\" \"About 
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Let the four consecutive integers be given by
\n" ); document.write( "N, N+2, N+4 and N+6\r
\n" ); document.write( "\n" ); document.write( "You are told that \"N+%2B+%28N%2B2%29+%2B+2%2A%28%28N%2B4%29%2B%28N%2B6%29%29+=+742\"
\n" ); document.write( "Solve for N
\n" ); document.write( "\"N+%2B+N+%2B+2+%2B+2N%2B8+%2B2N%2B12+=+742\"
\n" ); document.write( "\"6N+%2B+22+=+742\"
\n" ); document.write( "\"6N+=+720\"
\n" ); document.write( "\"N+=+120\"
\n" ); document.write( "So the numbers are 120, 122, 124, and 126\r
\n" ); document.write( "\n" ); document.write( "Check your answer. is \"742+=+120%2B122+%2B+2%28124%2B126%29\"
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