document.write( "Question 984681: Two numbers are 60% and 20% more than a third number. What is the second nuber expressed as a percentage of the first \n" ); document.write( "
Algebra.Com's Answer #605466 by vleith(2983)\"\" \"About 
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Let the third number be given by N
\n" ); document.write( "You are told a number is 60% more than N, so that is 1.6N
\n" ); document.write( "You are told a second number is 20% more than N, so that is 1.2N\r
\n" ); document.write( "\n" ); document.write( "You are asked to find how much more,percentage-wise, the first number is with respect to the second number.\r
\n" ); document.write( "\n" ); document.write( "\"%28%28Firstnumber%29%2F%28secondNumber%29%29+%2A+100++\" yields that result.
\n" ); document.write( "Plug in and get
\n" ); document.write( "\"%28%281.6N%29%2F%281.2N%29%29+%2A+100\" %
\n" ); document.write( "\"%281.6%2F1.2%29+%2A+100\"%
\n" ); document.write( "\"1.333+%2A+100\" %
\n" ); document.write( "\"133.33\" %\r
\n" ); document.write( "\n" ); document.write( "So the first number is 33.33% larger than the second one\r
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