document.write( "Question 984611: a restaurant serves meals at an average price of $12. the variable cost of each meal is $8 and fixed costs of running the restaurant amount to $400 per day.
\n" );
document.write( "i) if the restaurant sold 150 meals per day, determine the daily profit the restaurant would make
\n" );
document.write( "ii) how many meals should the restaurant aim to serve each day inorder to break even
\n" );
document.write( "iii) if the restaurant were making a loss of $200 per day, what increase in the number of meals served would be required to break even?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #605460 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a restaurant serves meals at an average price of $12. \n" ); document.write( " the variable cost of each meal is $8 and fixed costs of running the restaurant amount to $400 per day. \n" ); document.write( ": \n" ); document.write( "i) if the restaurant sold 150 meals per day, determine the daily profit the restaurant would make \n" ); document.write( "Let x = no. of meals sold \n" ); document.write( "Profit is the revenue (12x) minus the cost (8x+400) \n" ); document.write( "p(x) = 12x - (8x+400) \n" ); document.write( "p(x) = 12x - 8x - 400 (removing the bracket changes the sign \n" ); document.write( "p(x) = 4x - 400 \n" ); document.write( "If x = 150 \n" ); document.write( "p(x) = 4(150) - 400 \n" ); document.write( "p(x) = 600 - 400 \n" ); document.write( "p(x) $200 profit off of 150 meals \n" ); document.write( ": \n" ); document.write( "ii) how many meals should the restaurant aim to serve each day inorder to break even \n" ); document.write( "That's when revenue = cost \n" ); document.write( "12x = 8x + 400 \n" ); document.write( "12x - 8x = 400 \n" ); document.write( "4x = 400 \n" ); document.write( "x = 100 meals to break even \n" ); document.write( ": \n" ); document.write( "iii) if the restaurant were making a loss of $200 per day, what increase in the number of meals served would be required to break even? \n" ); document.write( "a loss is a negative profit, find how many meals sold for a $200 loss \n" ); document.write( "Use our profit equation to find x \n" ); document.write( " 4x - 400 = -200 \n" ); document.write( "4x = -200 + 400 \n" ); document.write( "4x = 200 \n" ); document.write( "x = 200/4 \n" ); document.write( "x = 50 meals cause a $200 loss \n" ); document.write( "we know the break-even point is 100 meals therefore a 50 meal increase is required. \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Made sense, right? \n" ); document.write( " \n" ); document.write( " |