document.write( "Question 84105: this is my problem:\r
\n" ); document.write( "\n" ); document.write( "let f(x)=5/x^2 and g(x)=6x=1\r
\n" ); document.write( "\n" ); document.write( "now it says to find (f 0 g)(x) and to find the domain of these\r
\n" ); document.write( "\n" ); document.write( "my first instinct is to multiply the two equations together and the domain is the x value of the answer, is this the correct procedure?\r
\n" ); document.write( "\n" ); document.write( "if it isnt will someone please lay out the steps for solving it for me \n" ); document.write( "
Algebra.Com's Answer #60544 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
let f(x)=5/x^2 and g(x)=6x+1
\n" ); document.write( "now it says to find (f 0 g)(x) and to find the domain of these
\n" ); document.write( "--------------
\n" ); document.write( "(fog)(x) means f[g(x)] \r
\n" ); document.write( "\n" ); document.write( "= f[6x+1]\r
\n" ); document.write( "\n" ); document.write( "= 5/(6x+1)^2\r
\n" ); document.write( "\n" ); document.write( "====================
\n" ); document.write( "Domain:
\n" ); document.write( "Since 6x+1 is in the denominator and since the denominator
\n" ); document.write( "cannot be zero, 6x+1 cannot be 0
\n" ); document.write( "So 6x cannot be -1
\n" ); document.write( "And finally, x cannot be -1/6
\n" ); document.write( "------
\n" ); document.write( "Domain of (fog)(x) is all Real Numbers except x=-1/6
\n" ); document.write( "===============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "
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