document.write( "Question 984652: Two brands of chocolates are available in pack of 24 and 15 respectively if i need to buy an eqyal number of chocolates of both kinds , what is the least no of boxes of each kind i would need to buy ? \n" ); document.write( "
Algebra.Com's Answer #605434 by josgarithmetic(39630)\"\" \"About 
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(1/24)(packages/pieces) and (1/15)(packages/pieces)\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F24=1%2F%282%2A12%29=1%2F%282%2A2%2A2%2A3%29\"\r
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\n" ); document.write( "\n" ); document.write( "and\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F15=1%2F%283%2A5%29\"\r
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\n" ); document.write( "\n" ); document.write( "This seems like common denominator or common multiple problem.\r
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\n" ); document.write( "\n" ); document.write( "The first denominator needs a 5 factor.
\n" ); document.write( "The second denominator needs a 2^3=8 factor.
\n" ); document.write( "The numerators also need the same corresponding factors, otherwise the quantity of packages will be missed.\r
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\n" ); document.write( "\n" ); document.write( "Box of 24:
\n" ); document.write( "\"%281%2F24%29%285%2F5%29=5%2F120\"
\n" ); document.write( "Buy 5 boxes.\r
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\n" ); document.write( "\n" ); document.write( "Box of 15:
\n" ); document.write( "\"%281%2F15%29%288%2F8%29=8%2F120\"
\n" ); document.write( "Buy 8 boxes.\r
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\n" ); document.write( "\n" ); document.write( "Buying 120 pieces of each of the chocolates.
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