document.write( "Question 984474: How long would I be walking backwards for ten minutes if it took 68 hundreths of a second for 5 meters, \n" ); document.write( "
Algebra.Com's Answer #605415 by Theo(13342)\"\" \"About 
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5 meters every 68 hundredths of a second.
\n" ); document.write( "10 minutes is equal to 10 * 60 = 600 seconds.
\n" ); document.write( "600 seconds divided by 68/100 is equal to 600 * 100 / 68 which is equal to 852.3529412 seconds
\n" ); document.write( "what this means is that 68/100 of a second divides into 10 minutes 882.3529412 times.
\n" ); document.write( "if you are traveling 5 meters every 68/100 of a second, then you will have traveled 5 * 882.3529412 = 4411.764706 meters in 10 minutes.\r
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\n" ); document.write( "\n" ); document.write( "another way of looking at it is as follows:\r
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\n" ); document.write( "\n" ); document.write( "you walk 5 meters in 68/100 of a second.
\n" ); document.write( "this means that you walk 7.352941176 meters in a second.
\n" ); document.write( "ten minutes is equal to 600 seconds.
\n" ); document.write( "600 * 7.352941176 = 4411.764706 meters.
\n" ); document.write( "same answer, as it should be.\r
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\n" ); document.write( "\n" ); document.write( "to test the reasonableness of the answer, do the following:
\n" ); document.write( "if you walk 7.352941176 meters in a second, then:
\n" ); document.write( "68/100 * 7.352941176 = 5 meters in 68/100 of a second.\r
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\n" ); document.write( "\n" ); document.write( "all the numbers check out except it is not likely that you could walk that fast whether you were going forwards or backwards.\r
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\n" ); document.write( "\n" ); document.write( "the average person walks about 3 miles per hour, going forward.\r
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\n" ); document.write( "\n" ); document.write( "that comes out to be about 20 minutes per mile.\r
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\n" ); document.write( "\n" ); document.write( "that means about 1/2 mile every 10 minutes.\r
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\n" ); document.write( "\n" ); document.write( "you're walking 2.73 miles in 10 minutes?\r
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\n" ); document.write( "\n" ); document.write( "not likely.\r
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