document.write( "Question 984629: A man driving his car at a certain speed from his home will reach his office in 6 hours. If he increased his speed by 24 kph, he would have reached his offce 1 hour less. Find the distance of his office from his home. \n" ); document.write( "
Algebra.Com's Answer #605411 by macston(5194)\"\" \"About 
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\n" ); document.write( "D=distance; R=original rate; T=original time
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\n" ); document.write( "Originally:
\n" ); document.write( "D=RT=R(6hrs)=6R hrs
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\n" ); document.write( "After speed increase:
\n" ); document.write( "D=(R+24kph)(6hrs-1hr)=(R+24kph)(5hrs)=5R hrs+120k
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\n" ); document.write( "Since distance to office is the same:
\n" ); document.write( "6R hrs=5R hrs +120k
\n" ); document.write( "R hrs=120k
\n" ); document.write( "R=120k/hr
\n" ); document.write( "His original speed was 120 kph.
\n" ); document.write( ".
\n" ); document.write( "(6hrs)(120kph)=720 km
\n" ); document.write( "The distance to his office was 720 kilometers.
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\n" ); document.write( "CHECK:
\n" ); document.write( "720km=(R+24kph)(6hrs-1hr)
\n" ); document.write( "720km=120kph+24kph)(5 hrs)
\n" ); document.write( "720km=(144kph)(5hrs)
\n" ); document.write( "720km=720km \n" ); document.write( "
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