document.write( "Question 984598: I have a function f (x) = 7/2x-1 and, if possible, am meant to \r
\n" ); document.write( "\n" ); document.write( "a) determine f(0), and \r
\n" ); document.write( "\n" ); document.write( "b) also simplify the quantity f(1+h)-f(1) \r
\n" ); document.write( "\n" ); document.write( "I do not really understand what about f(0) I am meant to determine, and also what the value 'h' is i the second part of the question.\r
\n" ); document.write( "\n" ); document.write( "help please?
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Algebra.Com's Answer #605383 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
a) f(0) is the value of the function when x equals zero,
\n" ); document.write( "So where there is an x, replace it with 0.
\n" ); document.write( "\"f%28x%29=7%2F%282x-1%29\"
\n" ); document.write( "\"f%280%29=7%2F%282%280%29-1%29\"
\n" ); document.write( "\"f%280%29=7%2F%280-1%29\"
\n" ); document.write( "\"f%280%29=7%2F%28-1%29\"
\n" ); document.write( "\"f%280%29=-7\"
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\n" ); document.write( "b) The value of h is unknown so keep it as a variable.
\n" ); document.write( "\"f%281%29=7%2F%282%281%29-1%29=7%2F%282-1%29=7%2F1=7\"
\n" ); document.write( "\"f%281%2Bh%29=7%2F%282%281%2Bh%29-1%29=7%2F%282%2B2h-1%29=7%2F%282h%2B1%29\"
\n" ); document.write( "So then,
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