document.write( "Question 984521: Diane is 23 years older than her daughter Amy. In six years, Diane will be twice as old as Amy. How old are they now. \n" ); document.write( "
Algebra.Com's Answer #605370 by Timnewman(323)![]() ![]() You can put this solution on YOUR website! Let her daughter' age be \"x\" \n" ); document.write( "Then Diane =x+23. \n" ); document.write( "In six years; \n" ); document.write( "Her daughter =x+6 \n" ); document.write( "Diane's age =(x+29) \n" ); document.write( "But Diane at six years will be twice as her daughter Amy \n" ); document.write( "Therfore, \n" ); document.write( "x+29=2(x+6) \n" ); document.write( "x+29=2x+12 \n" ); document.write( "2x-x=29-12 \n" ); document.write( "x=17 \n" ); document.write( "Amy's age = 17yrs \n" ); document.write( "Daine's age =x+23 \n" ); document.write( " =17+23 \n" ); document.write( " =40yrs \n" ); document.write( "HOPE THIS HELPS, \n" ); document.write( "Best regards, \n" ); document.write( "Timnewman:: \n" ); document.write( " |