document.write( "Question 984521: Diane is 23 years older than her daughter Amy. In six years, Diane will be twice as old as Amy. How old are they now. \n" ); document.write( "
Algebra.Com's Answer #605370 by Timnewman(323)\"\" \"About 
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Let her daughter' age be \"x\"
\n" ); document.write( "Then Diane =x+23.
\n" ); document.write( "In six years;
\n" ); document.write( "Her daughter =x+6
\n" ); document.write( "Diane's age =(x+29)
\n" ); document.write( "But Diane at six years will be twice as her daughter Amy
\n" ); document.write( "Therfore,
\n" ); document.write( "x+29=2(x+6)
\n" ); document.write( "x+29=2x+12
\n" ); document.write( "2x-x=29-12
\n" ); document.write( "x=17
\n" ); document.write( "Amy's age = 17yrs
\n" ); document.write( "Daine's age =x+23
\n" ); document.write( " =17+23
\n" ); document.write( " =40yrs
\n" ); document.write( "HOPE THIS HELPS,
\n" ); document.write( "Best regards,
\n" ); document.write( "Timnewman::
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