document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984486>Question 984486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The middle digit of a three digit number is zero. The number is 34 times the sum of its digits. The new number obtained by interchaning the digits in the units and hundreds place is more than the original number by 395. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #605295 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=605295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The middle digit of a three digit number is zero.<BR>\n" );
document.write( " The number is 34 times the sum of its digits.<BR>\n" );
document.write( " The new number obtained by interchanging the digits in the units and hundreds place is more than the original number by 395!!!!!<BR>\n" );
document.write( "In order for this to work it has to be a multiple of 9, 396 would work<BR>\n" );
document.write( " Find the original number.<BR>\n" );
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document.write( "let a = the 100's digit<BR>\n" );
document.write( "let b = the 10's digit which we know is 0<BR>\n" );
document.write( "let c = the units<BR>\n" );
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document.write( "The number is 34 times the sum of its digits.<BR>\n" );
document.write( "100a + c = 34(a + c)<BR>\n" );
document.write( "100a + c = 34a + 34c<BR>\n" );
document.write( "100a - 34a  = 34c - c<BR>\n" );
document.write( "66a = 33c<BR>\n" );
document.write( "simplify divide by 33<BR>\n" );
document.write( "2a = c\r<BR>\n" );
document.write( "\n" );
document.write( ":<BR>\n" );
document.write( "\"The new number obtained by interchaning the digits in the units and hundreds place is more than the original number by 396.\"<BR>\n" );
document.write( "100c + a = 100a + c + 396<BR>\n" );
document.write( "100c - c = 100a - a + 396<BR>\n" );
document.write( "99c = 99a + 396<BR>\n" );
document.write( "divide by 99<BR>\n" );
document.write( "c = a + 4<BR>\n" );
document.write( "Replace c with 2a<BR>\n" );
document.write( "2a = a + 4<BR>\n" );
document.write( "2a - a = 4<BR>\n" );
document.write( " a = 4<BR>\n" );
document.write( "then<BR>\n" );
document.write( "c = 4 + 4<BR>\n" );
document.write( "c = 8<BR>\n" );
document.write( ":<BR>\n" );
document.write( " Find the original number. It's 408 </SPAN>\n" );
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