document.write( "Question 984492: What is the smallest value, to 2 decimal places, in the image set of the function
\n" ); document.write( "f(x) = ax^2 + bx + c\r
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Algebra.Com's Answer #605278 by Edwin McCravy(20060) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "The smallest value of a quadratic function with a positive leading coefficient\r\n" );
document.write( "occurs at the vertex, of which the x-coordinate is .  The minimum\r\n" );
document.write( "value is the y-coordinate of the function when that x-coordinate is substituted\r\n" );
document.write( "for x in the function.  \r\n" );
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document.write( "The largest value of a quadratic function with a negative leading coefficient\r\n" );
document.write( "occurs at the vertex, of which the x-coordinate is .  The maximum\r\n" );
document.write( "value is the y-coordinate of the function when that x-coordinate is substituted\r\n" );
document.write( "for x in the function.  \r\n" );
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document.write( "Instead of doing your problem for you, I'll do one exactly in every step and\r\n" );
document.write( "detail like yours.  You can use it as a model to do yours.\r\n" );
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document.write( "f(x) = ax^2 + bx + c \r\n" );
document.write( "when a = 3, b = 12 and c = 127\r\n" );
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document.write( "f(x) = 3x^2 + 12x + 127\r\n" );
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document.write( "The x-coordinate of the vertex is\r\n" );
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document.write( " =  =  = \r\n" );
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document.write( "We find the y-ccordinate by substituting -2 for x in\r\n" );
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document.write( "f(x) = 3x^2 + 12x + 127\r\n" );
document.write( "f(2) = 3(-2)^2 + 12(-2) + 127\r\n" );
document.write( "f(2) = 3(4) - 24 + 127\r\n" );
document.write( "f(2) = 12 - 24 + 127\r\n" );
document.write( "f(2) = 115\r\n" );
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document.write( "So the minimum value is 115.\r\n" );
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document.write( "Now do yours exactly the same way.\r\n" );
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document.write( "Edwin

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