document.write( "Question 984483: evaluate tan 13pi/12 \n" ); document.write( "
Algebra.Com's Answer #605265 by srinivas.g(540)\"\" \"About 
You can put this solution on YOUR website!
pi = 180 degrees
\n" ); document.write( " \"13%2Api%2F12+=+13%2A180%2F12+\"
\n" ); document.write( " =\"+195\" degrees
\n" ); document.write( " hence tan (13pi/12)= tan(195)
\n" ); document.write( " tan(195)= tan (180+15)
\n" ); document.write( " = tan(15)
\n" ); document.write( " tan(15) = tan(60-45)
\n" ); document.write( "= \"%28tan%2860%29-tan%2845%29%29%2F%281%2Btan%2860%29%2Atan%2845%29%29\"
\n" ); document.write( "= \"%28sqrt%283%29-1%29%2F%281%2Bsqrt%283%29%2A1%29\"
\n" ); document.write( "Multiply numerator and denominator by \"1-sqrt%283%29\" to get:\r
\n" ); document.write( "\n" ); document.write( "\"%281-sqrt%283%29%29%5E2%2F%281-3%29\"
\n" ); document.write( "= \"%281-2sqrt%283%29%2B3%29%2F2\"
\n" ); document.write( "= \"%284-2sqrt%283%29%29%2F2\"
\n" ); document.write( "= \"2-sqrt%283%29\"
\n" ); document.write( "Result : \"2-sqrt%283%29\"
\n" ); document.write( "
\n" );