document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984466>Question 984466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the domain and range of this equation 3+2x-x^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #605250 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=605250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  3+2x-x^2=0  (editing to make it an equation rather than an expression)\r<BR>\n" );
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document.write( "x can be anything, all reals.  There are no constraints.<BR>\n" );
document.write( "If x is large and positive, y will be very negative.<BR>\n" );
document.write( "If x is large and negative, squaring it will make it positive and make y very negative.<BR>\n" );
document.write( "If x=0, y=3.  <BR>\n" );
document.write( "If x=1, Y=4<BR>\n" );
document.write( "if x=2, y=3\r<BR>\n" );
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document.write( "Vertex is -b/2a= -2/-2.  That is x=1<BR>\n" );
document.write( "Therefore the maximum is 4.<BR>\n" );
document.write( "Range is (-oo, 4]\r<BR>\n" );
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