document.write( "Question 984419: The area of a garden is 160 m2. Suppose the length of the length of the garden is 3 m more than twice its width. What is the length of the garden?
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Algebra.Com's Answer #605237 by Timnewman(323)\"\" \"About 
You can put this solution on YOUR website!
Hi dear,
\n" ); document.write( "Let L=lengh
\n" ); document.write( " w=width
\n" ); document.write( "If L*w=160----(1)
\n" ); document.write( "and L=3+2w---(2)
\n" ); document.write( "put (2) in (1)
\n" ); document.write( "(3+2w)w=160
\n" ); document.write( "2w²+3w-160=0
\n" ); document.write( "solving quadratic equation,
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"2x%5E2%2B3x%2B-160+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%283%29%5E2-4%2A2%2A-160=1289\".
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\n" ); document.write( " Discriminant d=1289 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-3%2B-sqrt%28+1289+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%283%29%2Bsqrt%28+1289+%29%29%2F2%5C2+=+8.22566153550812\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%283%29-sqrt%28+1289+%29%29%2F2%5C2+=+-9.72566153550812\"
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\n" ); document.write( " Quadratic expression \"2x%5E2%2B3x%2B-160\" can be factored:
\n" ); document.write( " \"2x%5E2%2B3x%2B-160+=+2%28x-8.22566153550812%29%2A%28x--9.72566153550812%29\"
\n" ); document.write( " Again, the answer is: 8.22566153550812, -9.72566153550812.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+2%2Ax%5E2%2B3%2Ax%2B-160+%29\"

\n" ); document.write( "\n" ); document.write( "Since w=8 aproximately,
\n" ); document.write( "put w=8 in in equ 2
\n" ); document.write( "there L=3+2*8
\n" ); document.write( " L=19m
\n" ); document.write( "the lenght is 19m
\n" ); document.write( "hope this helps;
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