document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=84055>Question 84055</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write equation for the line . Use slope intercept form if it its possible.\r<BR>\n" );
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document.write( "through (-1,4) perpendicular to 9x+5y=11\r<BR>\n" );
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document.write( "this is what i have done so far am i correct\r<BR>\n" );
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document.write( "9x+5y=11<BR>\n" );
document.write( "5y=-9x+11<BR>\n" );
document.write( "y=-(9)/(5)+(11)/(5)\r<BR>\n" );
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document.write( "so then i use the recipriocal slope which will be (5)/(9) and use the point that they gave me. so now i do the following:\r<BR>\n" );
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document.write( "y = mx+b<BR>\n" );
document.write( "4 = (5)/(9) * (-1) +b<BR>\n" );
document.write( "(41)/(9)=b\r<BR>\n" );
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document.write( "y= (5)/(9)x+(41)/(9)\r<BR>\n" );
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document.write( "#2<BR>\n" );
document.write( "through (3,-5),parallel to y =4\r<BR>\n" );
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document.write( "for this one ihave no idea?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #60520 by </B><A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><B>Edwin McCravy(20060)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Edwin+McCravy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=60520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write equation for the line . Use slope intercept form if it its possible. <BR>\n" );
document.write( "# 1<BR>\n" );
document.write( "through (-1,4) perpendicular to 9x+5y=11 <BR>\n" );
document.write( "this is what i have done so far am i correct <BR>\n" );
document.write( "9x+5y=11<BR>\n" );
document.write( "5y=-9x+11<BR>\n" );
document.write( "y=-(9)/(5)+(11)/(5) <BR>\n" );
document.write( "so then i use the reciprocal slope <b><font face = \"courier new\" color = \"red\"> with the opposite sign</font></b> <BR>\n" );
document.write( "which will be (5)/(9) and use the point that they gave me. so now i do the following: <BR>\n" );
document.write( "y = mx+b<BR>\n" );
document.write( "4 = (5)/(9) * (-1) +b<BR>\n" );
document.write( "(41)/(9)=b <BR>\n" );
document.write( "y= (5)/(9)x+(41)/(9) <BR>\n" );
document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\"><font color = \"red\"><b>\r\n" );
document.write( "That one is correct!\r\n" );
document.write( "</font></PRE> <BR>\n" );
document.write( "#2<BR>\n" );
document.write( "through (3,-5),parallel to y =4 <BR>\n" );
document.write( "for this one i have no idea?<BR>\n" );
document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\"><font color = \"red\"><b>\r\n" );
document.write( "y = 4 is this horizontal line\r\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C+-4%2C+10%2C+-7%2C+7%2C+4%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C+-4%2C+10%2C+-7%2C+7%2C+4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r\n" );
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document.write( "now plot the point (3,-5)\r\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C300%2C+-4%2C+10%2C+-7%2C+7%2C+%0D%0A%0D%0Alocate%282.8%2C-4.6%2C+%22o%3C--the_point_%283%2C-5%29%22%29%2C%0D%0Agraph%28300%2C300%2C+-4%2C+10%2C+-7%2C+7%2C+4%29+%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > \r\n" );
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document.write( "Now draw a green line parallel to\r\n" );
document.write( "the given line through that point.\r\n" );
document.write( "It will also be horizontal:\r\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28300%2C300%2C+-4%2C+10%2C+-7%2C+7%2C+%0D%0A%0D%0Alocate%282.8%2C-4.6%2C+o%29%2C%0D%0Agraph%28300%2C300%2C+-4%2C+10%2C+-7%2C+7%2C+4%2C+-5%29%2C%0D%0A%0D%0Alocate%281.8%2C-3.6%2C%22%283%2C-5%29%22%29%0D%0A+%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r\n" );
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document.write( "The equation of any horizontal line is y = b,\r\n" );
document.write( "where b is the y-coordinate of any and every \r\n" );
document.write( "point on the line.  So since (3,-5) is on the \r\n" );
document.write( "line and it has y-coordinate -5, the equation\r\n" );
document.write( "of the green line is y = -5.\r\n" );
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document.write( "Edwin</PRE> </SPAN>\n" );
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