document.write( "Question 11838: 3a-1/a^2+4a+4 - 3/a^2+2a = 3/a
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document.write( "this is a problem from my homework that is asking me to simply solve the equation. i don't know where or how to start to get the correct answer of
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document.write( "a = -9/8
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document.write( "any help with this would be greatly appreciated.
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document.write( "thanks \n" );
document.write( "
Algebra.Com's Answer #6052 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! i am assuming you mean \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, just fractions now...i will multiply both sides, that is ALL terms by the same thing, namely a(a+2)(a+2), as this is the lowest common factor of all three fractions. Doing this does not \"change\" the equation, it just \"scales\" it up a bit.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "By multiplying each term by the above, we can then cancel the fractions to leave:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "or 16a = -18 \n" ); document.write( "--> a = -18/16 \n" ); document.write( "--> a = -9/8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |