document.write( "Question 984306: If x^3 < 0, then sqrt (25x^2) +5x= ? \r
\n" ); document.write( "\n" ); document.write( "The answer is supposed to be 0, but I don't see how they got that.
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Algebra.Com's Answer #605090 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
sqrt(25x^2)+5x=\r
\n" ); document.write( "\n" ); document.write( "x^3<0, so x must be less than 0.
\n" ); document.write( "sqrt(25x^2) is normally +/-5x. It can be +5x or-5x.
\n" ); document.write( "BUT we know x<0.
\n" ); document.write( "Therefore, the sqrt (25x^2)= MINUS 5x ONLY.
\n" ); document.write( "-5x+5x=0.\r
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