document.write( "Question 984305: Find the domain of f(x)= { sqrt (x-5) if x>3
\n" ); document.write( " { 1/(x+5) if x<0\r
\n" ); document.write( "\n" ); document.write( "The answer is supposed to be (-infinity, -5) U (-5,0) U [5,infinity) \n" ); document.write( "

Algebra.Com's Answer #605088 by Fombitz(32388) $\"\"$ $\"About$

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The square root function is defined only when the argument is non-negative.
\n" ); document.write( " $\"x-5%3E=0\"$
\n" ); document.write( " $\"x%3E=5\"$
\n" ); document.write( "The rational function is defined everywhere except when the denominator equals zero.
\n" ); document.write( " $\"x%2B5=0\"$
\n" ); document.write( " $\"x=-5\"$
\n" ); document.write( "So the domain is all real numbers except $\"x=-5\"$ and between $\"x=0\"$ and $\"x=5\"$ .
\n" ); document.write( "So that would be,
\n" ); document.write( "( $\"-infinity\"$ , $\"-5\"$ )U( $\"-5\"$ , $\"0\"$ )U[ $\"5\"$ , $\"infinity\"$ )
\n" ); document.write( " \n" ); document.write( "

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