document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=984227>Question 984227</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider a vector v with direction angle &#952;=135° such that |v|=&#8730;2.<BR>\n" );
document.write( "Find the x-component.\r<BR>\n" );
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document.write( "Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #605006 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=605006\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> magnitude of vector v = |v|<BR>\n" );
document.write( "= square root of (2)<BR>\n" );
document.write( "theta = 135 degrees places it in quadrant 2 where x is negative and y is positive<BR>\n" );
document.write( "note |v| = square root of (2) = square root ( x^2 + y^2 ) = square root ( (-1^2) + 1^2 )<BR>\n" );
document.write( "therefore the x-component is -1\r<BR>\n" );
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