document.write( "Question 984230: Lamar has 46 coins, all nickels and dimes. The total value of all these coins is $3.05. How many nickels does he have? \n" ); document.write( "
| Algebra.Com's Answer #604997 by macston(5194)     You can put this solution on YOUR website! . \n" ); document.write( "N=number of nickels; D=number of dimes \n" ); document.write( "N+D=46 \n" ); document.write( "D=46-N Use this to substitute for D below. \n" ); document.write( ". \n" ); document.write( "$0.05N+$0.10D=$3.05 Substitute for D from above. \n" ); document.write( "$0.05N+$0.10(46-N)=$3.05 \n" ); document.write( "$0.05N+$4.60-$0.10N=$3.05 \n" ); document.write( "-$0.05N=-$1.55 \n" ); document.write( "31=N ANSWER: He has 31 nickels. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "D=46-N=46-31=15 He has 15 dimes \n" ); document.write( ". \n" ); document.write( "$0.05N+$0.10D=$3.05 \n" ); document.write( "$0.05(31)+$0.10(15)=$3.05 \n" ); document.write( "$1.55+$1.50=$3.05 \n" ); document.write( "$3.05=$3.05 \n" ); document.write( " \n" ); document.write( " |